34=3(n-5+1)

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Solution for 34=3(n-5+1) equation:



34=3(n-5+1)
We move all terms to the left:
34-(3(n-5+1))=0
We add all the numbers together, and all the variables
-(3(n-4))+34=0
We calculate terms in parentheses: -(3(n-4)), so:
3(n-4)
We multiply parentheses
3n-12
Back to the equation:
-(3n-12)
We get rid of parentheses
-3n+12+34=0
We add all the numbers together, and all the variables
-3n+46=0
We move all terms containing n to the left, all other terms to the right
-3n=-46
n=-46/-3
n=15+1/3

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