34=2h-18h/9h

Solution for 34=2h-18h/9h equation:

34=2h-18h/9h

We move all terms to the left:

34-(2h-18h/9h)=0


Domain of the equation: 9h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

-(+2h-18h/9h)+34=0

We get rid of parentheses

-2h+18h/9h+34=0

We multiply all the terms by the denominator


-2h*9h+18h+34*9h=0

We add all the numbers together, and all the variables

18h-2h*9h+34*9h=0

Wy multiply elements

-18h^2+18h+306h=0

We add all the numbers together, and all the variables

-18h^2+324h=0

a = -18; b = 324; c = 0;
Δ = b2-4ac
Δ = 3242-4·(-18)·0
Δ = 104976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{104976}=324$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(324)-324}{2*-18}=\frac{-648}{-36}
=+18
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(324)+324}{2*-18}=\frac{0}{-36}
=0
$