348=1/2(12)(x-15)

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Solution for 348=1/2(12)(x-15) equation:



348=1/2(12)(x-15)
We move all terms to the left:
348-(1/2(12)(x-15))=0
Domain of the equation: 212(x-15))!=0
x∈R
We multiply all the terms by the denominator
-(1+348*212(x-15))=0
We calculate terms in parentheses: -(1+348*212(x-15)), so:
1+348*212(x-15)
determiningTheFunctionDomain 348*212(x-15)+1
Wy multiply elements
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Back to the equation:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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We calculate terms in parentheses: -(73776x(x+1), so:
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