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34-4(3-2x)=7x-2(x-5)
We move all terms to the left:
34-4(3-2x)-(7x-2(x-5))=0
We add all the numbers together, and all the variables
-4(-2x+3)-(7x-2(x-5))+34=0
We multiply parentheses
8x-(7x-2(x-5))-12+34=0
We calculate terms in parentheses: -(7x-2(x-5)), so:We add all the numbers together, and all the variables
7x-2(x-5)
We multiply parentheses
7x-2x+10
We add all the numbers together, and all the variables
5x+10
Back to the equation:
-(5x+10)
8x-(5x+10)+22=0
We get rid of parentheses
8x-5x-10+22=0
We add all the numbers together, and all the variables
3x+12=0
We move all terms containing x to the left, all other terms to the right
3x=-12
x=-12/3
x=-4
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