34-(3c+4)=2(c+6)=c

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Solution for 34-(3c+4)=2(c+6)=c equation: 



34-(3c+4)=2(c+6)=c

We move all terms to the left:

34-(3c+4)-(2(c+6))=0

We get rid of parentheses

-3c-(2(c+6))-4+34=0



We calculate terms in parentheses: -(2(c+6)), so:

2(c+6)

We multiply parentheses

2c+12

Back to the equation:

-(2c+12)



We add all the numbers together, and all the variables

-3c-(2c+12)+30=0

We get rid of parentheses

-3c-2c-12+30=0

We add all the numbers together, and all the variables

-5c+18=0

We move all terms containing c to the left, all other terms to the right

-5c=-18

c=-18/-5

c=3+3/5

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