34-(2c+4)=2(c+5)+5

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Solution for 34-(2c+4)=2(c+5)+5 equation: 



34-(2c+4)=2(c+5)+5

We move all terms to the left:

34-(2c+4)-(2(c+5)+5)=0

We get rid of parentheses

-2c-(2(c+5)+5)-4+34=0



We calculate terms in parentheses: -(2(c+5)+5), so:

2(c+5)+5

We multiply parentheses

2c+10+5

We add all the numbers together, and all the variables

2c+15

Back to the equation:

-(2c+15)



We add all the numbers together, and all the variables

-2c-(2c+15)+30=0

We get rid of parentheses

-2c-2c-15+30=0

We add all the numbers together, and all the variables

-4c+15=0

We move all terms containing c to the left, all other terms to the right

-4c=-15

c=-15/-4

c=3+3/4

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