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34-(2c+3)=2(c+5)+c
We move all terms to the left:
34-(2c+3)-(2(c+5)+c)=0
We get rid of parentheses
-2c-(2(c+5)+c)-3+34=0
We calculate terms in parentheses: -(2(c+5)+c), so:We add all the numbers together, and all the variables
2(c+5)+c
We add all the numbers together, and all the variables
c+2(c+5)
We multiply parentheses
c+2c+10
We add all the numbers together, and all the variables
3c+10
Back to the equation:
-(3c+10)
-2c-(3c+10)+31=0
We get rid of parentheses
-2c-3c-10+31=0
We add all the numbers together, and all the variables
-5c+21=0
We move all terms containing c to the left, all other terms to the right
-5c=-21
c=-21/-5
c=4+1/5
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