34(3c+4)=2(c+6)+c

Solution for 34(3c+4)=2(c+6)+c equation:

34(3c+4)=2(c+6)+c

We move all terms to the left:

34(3c+4)-(2(c+6)+c)=0

We multiply parentheses

102c-(2(c+6)+c)+136=0


We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)


We get rid of parentheses

102c-3c-12+136=0

We add all the numbers together, and all the variables

99c+124=0

We move all terms containing c to the left, all other terms to the right

99c=-124

c=-124/99

c=-1+25/99