33x-5(6x+7)/100=10-8(3x-1)/50

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Solution for 33x-5(6x+7)/100=10-8(3x-1)/50 equation: 



33x-5(6x+7)/100=10-8(3x-1)/50

We move all terms to the left:

33x-5(6x+7)/100-(10-8(3x-1)/50)=0

We calculate fractions


33x+(-30x)/()+(-(10-8(3x-1)*100)/()=0



We calculate terms in parentheses: +(-(10-8(3x-1)*100)/(), so:

-(10-8(3x-1)*100)/(

We multiply all the terms by the denominator


-(10-8(3x-1)*100)



We calculate terms in parentheses: -(10-8(3x-1)*100), so:

10-8(3x-1)*100

determiningTheFunctionDomain
-8(3x-1)*100+10

We multiply parentheses

-2400x+800+10

We add all the numbers together, and all the variables

-2400x+810

Back to the equation:

-(-2400x+810)



We get rid of parentheses

2400x-810

Back to the equation:

+(2400x-810)



We get rid of parentheses

33x+(-30x)/()+2400x-810=0

We multiply all the terms by the denominator


33x*()+(-30x)+2400x*()-810*()=0

We add all the numbers together, and all the variables

33x*()+(-30x)+2400x*()=0

We get rid of parentheses

33x*()-30x+2400x*()=0

We add all the numbers together, and all the variables

-30x+33x*()+2400x*()=0

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