33=6(u+3)-3u

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Solution for 33=6(u+3)-3u equation: 



33=6(u+3)-3u

We move all terms to the left:

33-(6(u+3)-3u)=0



We calculate terms in parentheses: -(6(u+3)-3u), so:

6(u+3)-3u

We add all the numbers together, and all the variables

-3u+6(u+3)

We multiply parentheses

-3u+6u+18

We add all the numbers together, and all the variables

3u+18

Back to the equation:

-(3u+18)



We get rid of parentheses

-3u-18+33=0

We add all the numbers together, and all the variables

-3u+15=0

We move all terms containing u to the left, all other terms to the right

-3u=-15

u=-15/-3

u=+5

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