33=-3c+5(3+c)

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Solution for 33=-3c+5(3+c) equation: 



33=-3c+5(3+c)

We move all terms to the left:

33-(-3c+5(3+c))=0

We add all the numbers together, and all the variables

-(-3c+5(c+3))+33=0



We calculate terms in parentheses: -(-3c+5(c+3)), so:

-3c+5(c+3)

We multiply parentheses

-3c+5c+15

We add all the numbers together, and all the variables

2c+15

Back to the equation:

-(2c+15)



We get rid of parentheses

-2c-15+33=0

We add all the numbers together, and all the variables

-2c+18=0

We move all terms containing c to the left, all other terms to the right

-2c=-18

c=-18/-2

c=+9

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