33=-3b-3(1+3b)

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Solution for 33=-3b-3(1+3b) equation: 



33=-3b-3(1+3b)

We move all terms to the left:

33-(-3b-3(1+3b))=0

We add all the numbers together, and all the variables

-(-3b-3(3b+1))+33=0



We calculate terms in parentheses: -(-3b-3(3b+1)), so:

-3b-3(3b+1)

We multiply parentheses

-3b-9b-3

We add all the numbers together, and all the variables

-12b-3

Back to the equation:

-(-12b-3)



We get rid of parentheses

12b+3+33=0

We add all the numbers together, and all the variables

12b+36=0

We move all terms containing b to the left, all other terms to the right

12b=-36

b=-36/12

b=-3

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