330=2w+2(2/3w)

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Solution for 330=2w+2(2/3w) equation:



330=2w+2(2/3w)
We move all terms to the left:
330-(2w+2(2/3w))=0
Domain of the equation: 3w))!=0
w!=0/1
w!=0
w∈R
We add all the numbers together, and all the variables
-(2w+2(+2/3w))+330=0
We multiply all the terms by the denominator
-(2w+2(+2+330*3w))=0
We calculate terms in parentheses: -(2w+2(+2+330*3w)), so:
2w+2(+2+330*3w)
We add all the numbers together, and all the variables
2w+2(330*3w+2)
We multiply parentheses
2w+1980w+4
We add all the numbers together, and all the variables
1982w+4
Back to the equation:
-(1982w+4)
We get rid of parentheses
-1982w-4=0
We move all terms containing w to the left, all other terms to the right
-1982w=4
w=4/-1982
w=-2/991

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