33/p=3p=11

Solution for 33/p=3p=11 equation:

33/p=3p=11

We move all terms to the left:

33/p-(3p)=0


Domain of the equation: p!=0

p∈R


We add all the numbers together, and all the variables

-3p+33/p=0

We multiply all the terms by the denominator


-3p*p+33=0

Wy multiply elements

-3p^2+33=0

a = -3; b = 0; c = +33;
Δ = b2-4ac
Δ = 02-4·(-3)·33
Δ = 396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{396}=\sqrt{36*11}=\sqrt{36}*\sqrt{11}=6\sqrt{11}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{11}}{2*-3}=\frac{0-6\sqrt{11}}{-6}
=-\frac{6\sqrt{11}}{-6}
=-\frac{\sqrt{11}}{-1}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{11}}{2*-3}=\frac{0+6\sqrt{11}}{-6}
=\frac{6\sqrt{11}}{-6}
=\frac{\sqrt{11}}{-1}
$