33-(2c=3)=2(c=5)=c

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Solution for 33-(2c=3)=2(c=5)=c equation: 



33-(2c=3)=2(c=5)=c

We move all terms to the left:

33-(2c-(3))=0

We get rid of parentheses

-2c+3+33=0

We add all the numbers together, and all the variables

-2c+36=0

We move all terms containing c to the left, all other terms to the right

-2c=-36

c=-36/-2

c=+18

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