33-(2c+4)=2(c+7+c)

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Solution for 33-(2c+4)=2(c+7+c) equation:


Simplifying
33 + -1(2c + 4) = 2(c + 7 + c)

Reorder the terms:
33 + -1(4 + 2c) = 2(c + 7 + c)
33 + (4 * -1 + 2c * -1) = 2(c + 7 + c)
33 + (-4 + -2c) = 2(c + 7 + c)

Combine like terms: 33 + -4 = 29
29 + -2c = 2(c + 7 + c)

Reorder the terms:
29 + -2c = 2(7 + c + c)

Combine like terms: c + c = 2c
29 + -2c = 2(7 + 2c)
29 + -2c = (7 * 2 + 2c * 2)
29 + -2c = (14 + 4c)

Solving
29 + -2c = 14 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
29 + -2c + -4c = 14 + 4c + -4c

Combine like terms: -2c + -4c = -6c
29 + -6c = 14 + 4c + -4c

Combine like terms: 4c + -4c = 0
29 + -6c = 14 + 0
29 + -6c = 14

Add '-29' to each side of the equation.
29 + -29 + -6c = 14 + -29

Combine like terms: 29 + -29 = 0
0 + -6c = 14 + -29
-6c = 14 + -29

Combine like terms: 14 + -29 = -15
-6c = -15

Divide each side by '-6'.
c = 2.5

Simplifying
c = 2.5

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