33-(2-4x)+2x=2(7x+3)-3

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Solution for 33-(2-4x)+2x=2(7x+3)-3 equation: 



33-(2-4x)+2x=2(7x+3)-3

We move all terms to the left:

33-(2-4x)+2x-(2(7x+3)-3)=0

We add all the numbers together, and all the variables

-(-4x+2)+2x-(2(7x+3)-3)+33=0

We add all the numbers together, and all the variables

2x-(-4x+2)-(2(7x+3)-3)+33=0

We get rid of parentheses

2x+4x-(2(7x+3)-3)-2+33=0



We calculate terms in parentheses: -(2(7x+3)-3), so:

2(7x+3)-3

We multiply parentheses

14x+6-3

We add all the numbers together, and all the variables

14x+3

Back to the equation:

-(14x+3)



We add all the numbers together, and all the variables

6x-(14x+3)+31=0

We get rid of parentheses

6x-14x-3+31=0

We add all the numbers together, and all the variables

-8x+28=0

We move all terms containing x to the left, all other terms to the right

-8x=-28

x=-28/-8

x=3+1/2

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