33(2x+1)=8x+21

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Solution for 33(2x+1)=8x+21 equation: 



33(2x+1)=8x+21

We move all terms to the left:

33(2x+1)-(8x+21)=0

We multiply parentheses

66x-(8x+21)+33=0

We get rid of parentheses

66x-8x-21+33=0

We add all the numbers together, and all the variables

58x+12=0

We move all terms containing x to the left, all other terms to the right

58x=-12

x=-12/58

x=-6/29

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