32y-4=(8y-1)

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Solution for 32y-4=(8y-1) equation: 



32y-4=(8y-1)

We move all terms to the left:

32y-4-((8y-1))=0



We calculate terms in parentheses: -((8y-1)), so:

(8y-1)

We get rid of parentheses

8y-1

Back to the equation:

-(8y-1)



We get rid of parentheses

32y-8y+1-4=0

We add all the numbers together, and all the variables

24y-3=0

We move all terms containing y to the left, all other terms to the right

24y=3

y=3/24

y=1/8

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