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32y-2y*y=126
We move all terms to the left:
32y-2y*y-(126)=0
Wy multiply elements
-2y^2+32y-126=0
a = -2; b = 32; c = -126;
Δ = b2-4ac
Δ = 322-4·(-2)·(-126)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4}{2*-2}=\frac{-36}{-4} =+9 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4}{2*-2}=\frac{-28}{-4} =+7 $
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