32y+48=16(3y+2)

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Solution for 32y+48=16(3y+2) equation: 



32y+48=16(3y+2)

We move all terms to the left:

32y+48-(16(3y+2))=0



We calculate terms in parentheses: -(16(3y+2)), so:

16(3y+2)

We multiply parentheses

48y+32

Back to the equation:

-(48y+32)



We get rid of parentheses

32y-48y-32+48=0

We add all the numbers together, and all the variables

-16y+16=0

We move all terms containing y to the left, all other terms to the right

-16y=-16

y=-16/-16

y=1

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