32x-8/(3x)=10

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Solution for 32x-8/(3x)=10 equation:


D( x )

3*x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

32*x-(8/(3*x)) = 10 // - 10

32*x-(8/(3*x))-10 = 0

32*x+(-8/3)*x^-1-10 = 0

32*x^1-8/3*x^-1-10*x^0 = 0

(32*x^2-10*x^1-8/3*x^0)/(x^1) = 0 // * x^2

x^1*(32*x^2-10*x^1-8/3*x^0) = 0

x^1

32*x^2-10*x-8/3 = 0

32*x^2-10*x-8/3 = 0

DELTA = (-10)^2-(4*32*(-8/3))

DELTA = 1324/3

DELTA > 0

x = ((1324/3)^(1/2)+10)/(2*32) or x = (10-(1324/3)^(1/2))/(2*32)

x = ((1324/3)^(1/2)+10)/64 or x = (10-(1324/3)^(1/2))/64

x in { (10-(1324/3)^(1/2))/64, ((1324/3)^(1/2)+10)/64}

x in { (10-(1324/3)^(1/2))/64, ((1324/3)^(1/2)+10)/64 }

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