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32s^2-8=0
a = 32; b = 0; c = -8;
Δ = b2-4ac
Δ = 02-4·32·(-8)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*32}=\frac{-32}{64} =-1/2 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*32}=\frac{32}{64} =1/2 $
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