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32=x-9/5x
We move all terms to the left:
32-(x-9/5x)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+x-9/5x)+32=0
We get rid of parentheses
-x+9/5x+32=0
We multiply all the terms by the denominator
-x*5x+32*5x+9=0
Wy multiply elements
-5x^2+160x+9=0
a = -5; b = 160; c = +9;
Δ = b2-4ac
Δ = 1602-4·(-5)·9
Δ = 25780
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25780}=\sqrt{4*6445}=\sqrt{4}*\sqrt{6445}=2\sqrt{6445}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-2\sqrt{6445}}{2*-5}=\frac{-160-2\sqrt{6445}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+2\sqrt{6445}}{2*-5}=\frac{-160+2\sqrt{6445}}{-10} $
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