32=9/5c+23

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Solution for 32=9/5c+23 equation: 



32=9/5c+23

We move all terms to the left:

32-(9/5c+23)=0



Domain of the equation: 5c+23)!=0

c∈R



We get rid of parentheses

-9/5c-23+32=0

We multiply all the terms by the denominator


-23*5c+32*5c-9=0

Wy multiply elements

-115c+160c-9=0

We add all the numbers together, and all the variables

45c-9=0

We move all terms containing c to the left, all other terms to the right

45c=9

c=9/45

c=1/5

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