32=7-5/2(8r-6)+2r

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Solution for 32=7-5/2(8r-6)+2r equation: 



32=7-5/2(8r-6)+2r

We move all terms to the left:

32-(7-5/2(8r-6)+2r)=0



Domain of the equation: 2(8r-6)+2r)!=0

r∈R



We multiply all the terms by the denominator


-(7-5+32*2(8r-6)+2r)=0



We calculate terms in parentheses: -(7-5+32*2(8r-6)+2r), so:

7-5+32*2(8r-6)+2r

determiningTheFunctionDomain
32*2(8r-6)+2r+7-5

We add all the numbers together, and all the variables

2r+32*2(8r-6)+2

Wy multiply elements

2r+64r(8+2

Back to the equation:

-(2r+64r(8+2)



We add all the numbers together, and all the variables

-(2r+64r10=0

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