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32=67t-4.9t^2
We move all terms to the left:
32-(67t-4.9t^2)=0
We get rid of parentheses
4.9t^2-67t+32=0
a = 4.9; b = -67; c = +32;
Δ = b2-4ac
Δ = -672-4·4.9·32
Δ = 3861.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-67)-\sqrt{3861.8}}{2*4.9}=\frac{67-\sqrt{3861.8}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-67)+\sqrt{3861.8}}{2*4.9}=\frac{67+\sqrt{3861.8}}{9.8} $
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