32=4(y+4)-6y

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Solution for 32=4(y+4)-6y equation: 



32=4(y+4)-6y

We move all terms to the left:

32-(4(y+4)-6y)=0



We calculate terms in parentheses: -(4(y+4)-6y), so:

4(y+4)-6y

We add all the numbers together, and all the variables

-6y+4(y+4)

We multiply parentheses

-6y+4y+16

We add all the numbers together, and all the variables

-2y+16

Back to the equation:

-(-2y+16)



We get rid of parentheses

2y-16+32=0

We add all the numbers together, and all the variables

2y+16=0

We move all terms containing y to the left, all other terms to the right

2y=-16

y=-16/2

y=-8

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