32=4(c+80)+-8

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Solution for 32=4(c+80)+-8 equation: 



32=4(c+80)+-8

We move all terms to the left:

32-(4(c+80)+-8)=0

We use the square of the difference formula

-(4(c+80)-8)+32=0



We calculate terms in parentheses: -(4(c+80)-8), so:

4(c+80)-8

We multiply parentheses

4c+320-8

We add all the numbers together, and all the variables

4c+312

Back to the equation:

-(4c+312)



We get rid of parentheses

-4c-312+32=0

We add all the numbers together, and all the variables

-4c-280=0

We move all terms containing c to the left, all other terms to the right

-4c=280

c=280/-4

c=-70

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