32=3y+(y+8)

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Solution for 32=3y+(y+8) equation: 



32=3y+(y+8)

We move all terms to the left:

32-(3y+(y+8))=0



We calculate terms in parentheses: -(3y+(y+8)), so:

3y+(y+8)

We get rid of parentheses

3y+y+8

We add all the numbers together, and all the variables

4y+8

Back to the equation:

-(4y+8)



We get rid of parentheses

-4y-8+32=0

We add all the numbers together, and all the variables

-4y+24=0

We move all terms containing y to the left, all other terms to the right

-4y=-24

y=-24/-4

y=+6

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