32=2(10-x)+2(3x+10)

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Solution for 32=2(10-x)+2(3x+10) equation: 



32=2(10-x)+2(3x+10)

We move all terms to the left:

32-(2(10-x)+2(3x+10))=0

We add all the numbers together, and all the variables

-(2(-1x+10)+2(3x+10))+32=0



We calculate terms in parentheses: -(2(-1x+10)+2(3x+10)), so:

2(-1x+10)+2(3x+10)

We multiply parentheses

-2x+6x+20+20

We add all the numbers together, and all the variables

4x+40

Back to the equation:

-(4x+40)



We get rid of parentheses

-4x-40+32=0

We add all the numbers together, and all the variables

-4x-8=0

We move all terms containing x to the left, all other terms to the right

-4x=8

x=8/-4

x=-2

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