32=128/w+2w

Solution for 32=128/w+2w equation:

32=128/w+2w

We move all terms to the left:

32-(128/w+2w)=0


Domain of the equation: w+2w)!=0

w∈R


We add all the numbers together, and all the variables

-(+2w+128/w)+32=0

We get rid of parentheses

-2w-128/w+32=0

We multiply all the terms by the denominator


-2w*w+32*w-128=0

We add all the numbers together, and all the variables

32w-2w*w-128=0

Wy multiply elements

-2w^2+32w-128=0

a = -2; b = 32; c = -128;
Δ = b2-4ac
Δ = 322-4·(-2)·(-128)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{-32}{-4}=+8$