32=-3(1-x)-8(-8x-4)

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Solution for 32=-3(1-x)-8(-8x-4) equation: 



32=-3(1-x)-8(-8x-4)

We move all terms to the left:

32-(-3(1-x)-8(-8x-4))=0

We add all the numbers together, and all the variables

-(-3(-1x+1)-8(-8x-4))+32=0



We calculate terms in parentheses: -(-3(-1x+1)-8(-8x-4)), so:

-3(-1x+1)-8(-8x-4)

We multiply parentheses

3x+64x-3+32

We add all the numbers together, and all the variables

67x+29

Back to the equation:

-(67x+29)



We get rid of parentheses

-67x-29+32=0

We add all the numbers together, and all the variables

-67x+3=0

We move all terms containing x to the left, all other terms to the right

-67x=-3

x=-3/-67

x=3/67

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