327x-4/x+5

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Solution for 327x-4/x+5 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

327*x-(4/x)+5 = 0

327*x-4*x^-1+5 = 0

327*x^1-4*x^-1+5*x^0 = 0

(327*x^2+5*x^1-4*x^0)/(x^1) = 0 // * x^2

x^1*(327*x^2+5*x^1-4*x^0) = 0

x^1

327*x^2+5*x-4 = 0

327*x^2+5*x-4 = 0

DELTA = 5^2-(-4*4*327)

DELTA = 5257

DELTA > 0

x = (5257^(1/2)-5)/(2*327) or x = (-5257^(1/2)-5)/(2*327)

x = (5257^(1/2)-5)/654 or x = (-(5257^(1/2)+5))/654

x in { (-(5257^(1/2)+5))/654, (5257^(1/2)-5)/654}

x in { (-(5257^(1/2)+5))/654, (5257^(1/2)-5)/654 }

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