320+32x=3200-200x

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Solution for 320+32x=3200-200x equation:



320+32x=3200-200x
We move all terms to the left:
320+32x-(3200-200x)=0
We add all the numbers together, and all the variables
32x-(-200x+3200)+320=0
We get rid of parentheses
32x+200x-3200+320=0
We add all the numbers together, and all the variables
232x-2880=0
We move all terms containing x to the left, all other terms to the right
232x=2880
x=2880/232
x=12+12/29

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