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32/(2x-5)-3=1/4
We move all terms to the left:
32/(2x-5)-3-(1/4)=0
Domain of the equation: (2x-5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
2x!=5
x!=5/2
x!=2+1/2
x∈R
32/(2x-5)-3-(+1/4)=0
We get rid of parentheses
32/(2x-5)-3-1/4=0
We calculate fractions
There is no solution for this equation
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