32-8x=3x-4(2x-5)

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Solution for 32-8x=3x-4(2x-5) equation: 



32-8x=3x-4(2x-5)

We move all terms to the left:

32-8x-(3x-4(2x-5))=0



We calculate terms in parentheses: -(3x-4(2x-5)), so:

3x-4(2x-5)

We multiply parentheses

3x-8x+20

We add all the numbers together, and all the variables

-5x+20

Back to the equation:

-(-5x+20)



We get rid of parentheses

-8x+5x-20+32=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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