32-4z=2(z-5)

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Solution for 32-4z=2(z-5) equation: 



32-4z=2(z-5)

We move all terms to the left:

32-4z-(2(z-5))=0



We calculate terms in parentheses: -(2(z-5)), so:

2(z-5)

We multiply parentheses

2z-10

Back to the equation:

-(2z-10)



We get rid of parentheses

-4z-2z+10+32=0

We add all the numbers together, and all the variables

-6z+42=0

We move all terms containing z to the left, all other terms to the right

-6z=-42

z=-42/-6

z=+7

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