32-4z=2(z-2)

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Solution for 32-4z=2(z-2) equation:



32-4z=2(z-2)
We move all terms to the left:
32-4z-(2(z-2))=0
We calculate terms in parentheses: -(2(z-2)), so:
2(z-2)
We multiply parentheses
2z-4
Back to the equation:
-(2z-4)
We get rid of parentheses
-4z-2z+4+32=0
We add all the numbers together, and all the variables
-6z+36=0
We move all terms containing z to the left, all other terms to the right
-6z=-36
z=-36/-6
z=+6

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