32-4x=3x+5(1+4x)

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Solution for 32-4x=3x+5(1+4x) equation: 



32-4x=3x+5(1+4x)

We move all terms to the left:

32-4x-(3x+5(1+4x))=0

We add all the numbers together, and all the variables

-4x-(3x+5(4x+1))+32=0



We calculate terms in parentheses: -(3x+5(4x+1)), so:

3x+5(4x+1)

We multiply parentheses

3x+20x+5

We add all the numbers together, and all the variables

23x+5

Back to the equation:

-(23x+5)



We get rid of parentheses

-4x-23x-5+32=0

We add all the numbers together, and all the variables

-27x+27=0

We move all terms containing x to the left, all other terms to the right

-27x=-27

x=-27/-27

x=1

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