32-4n=2(7+n)

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Solution for 32-4n=2(7+n) equation: 



32-4n=2(7+n)

We move all terms to the left:

32-4n-(2(7+n))=0

We add all the numbers together, and all the variables

-4n-(2(n+7))+32=0



We calculate terms in parentheses: -(2(n+7)), so:

2(n+7)

We multiply parentheses

2n+14

Back to the equation:

-(2n+14)



We get rid of parentheses

-4n-2n-14+32=0

We add all the numbers together, and all the variables

-6n+18=0

We move all terms containing n to the left, all other terms to the right

-6n=-18

n=-18/-6

n=+3

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