32-(3x+4)=2(x+5)+x

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Solution for 32-(3x+4)=2(x+5)+x equation: 



32-(3x+4)=2(x+5)+x

We move all terms to the left:

32-(3x+4)-(2(x+5)+x)=0

We get rid of parentheses

-3x-(2(x+5)+x)-4+32=0



We calculate terms in parentheses: -(2(x+5)+x), so:

2(x+5)+x

We add all the numbers together, and all the variables

x+2(x+5)

We multiply parentheses

x+2x+10

We add all the numbers together, and all the variables

3x+10

Back to the equation:

-(3x+10)



We add all the numbers together, and all the variables

-3x-(3x+10)+28=0

We get rid of parentheses

-3x-3x-10+28=0

We add all the numbers together, and all the variables

-6x+18=0

We move all terms containing x to the left, all other terms to the right

-6x=-18

x=-18/-6

x=+3

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