32-(10/4.a+12)=12

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Solution for 32-(10/4.a+12)=12 equation: 



32-(10/4.a+12)=12

We move all terms to the left:

32-(10/4.a+12)-(12)=0



Domain of the equation: 4.a+12)!=0

a∈R



We add all the numbers together, and all the variables

-(10/4.a+12)+20=0

We get rid of parentheses

-10/4.a-12+20=0

We multiply all the terms by the denominator


-12*4.a+20*4.a-10=0

Wy multiply elements

-48a+80a-10=0

We add all the numbers together, and all the variables

32a-10=0

We move all terms containing a to the left, all other terms to the right

32a=10

a=10/32

a=5/16

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