32+2x=8(1+3x)+2

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Solution for 32+2x=8(1+3x)+2 equation: 



32+2x=8(1+3x)+2

We move all terms to the left:

32+2x-(8(1+3x)+2)=0

We add all the numbers together, and all the variables

2x-(8(3x+1)+2)+32=0



We calculate terms in parentheses: -(8(3x+1)+2), so:

8(3x+1)+2

We multiply parentheses

24x+8+2

We add all the numbers together, and all the variables

24x+10

Back to the equation:

-(24x+10)



We get rid of parentheses

2x-24x-10+32=0

We add all the numbers together, and all the variables

-22x+22=0

We move all terms containing x to the left, all other terms to the right

-22x=-22

x=-22/-22

x=1

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