32+2v=5(1+6v)-1

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Solution for 32+2v=5(1+6v)-1 equation:


Simplifying
32 + 2v = 5(1 + 6v) + -1
32 + 2v = (1 * 5 + 6v * 5) + -1
32 + 2v = (5 + 30v) + -1

Reorder the terms:
32 + 2v = 5 + -1 + 30v

Combine like terms: 5 + -1 = 4
32 + 2v = 4 + 30v

Solving
32 + 2v = 4 + 30v

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-30v' to each side of the equation.
32 + 2v + -30v = 4 + 30v + -30v

Combine like terms: 2v + -30v = -28v
32 + -28v = 4 + 30v + -30v

Combine like terms: 30v + -30v = 0
32 + -28v = 4 + 0
32 + -28v = 4

Add '-32' to each side of the equation.
32 + -32 + -28v = 4 + -32

Combine like terms: 32 + -32 = 0
0 + -28v = 4 + -32
-28v = 4 + -32

Combine like terms: 4 + -32 = -28
-28v = -28

Divide each side by '-28'.
v = 1

Simplifying
v = 1

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