32(x+10)+29x+3(x-5)=945)

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Solution for 32(x+10)+29x+3(x-5)=945) equation: 



32(x+10)+29x+3(x-5)=945)

We move all terms to the left:

32(x+10)+29x+3(x-5)-(945))=0

We add all the numbers together, and all the variables

29x+32(x+10)+3(x-5)=0

We multiply parentheses

29x+32x+3x+320-15=0

We add all the numbers together, and all the variables

64x+305=0

We move all terms containing x to the left, all other terms to the right

64x=-305

x=-305/64

x=-4+49/64

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