32(2x+6)=3x+3

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Solution for 32(2x+6)=3x+3 equation: 



32(2x+6)=3x+3

We move all terms to the left:

32(2x+6)-(3x+3)=0

We multiply parentheses

64x-(3x+3)+192=0

We get rid of parentheses

64x-3x-3+192=0

We add all the numbers together, and all the variables

61x+189=0

We move all terms containing x to the left, all other terms to the right

61x=-189

x=-189/61

x=-3+6/61

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