31b-7(21-38b)=8(32+36b)-22b

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Solution for 31b-7(21-38b)=8(32+36b)-22b equation: 



31b-7(21-38b)=8(32+36b)-22b

We move all terms to the left:

31b-7(21-38b)-(8(32+36b)-22b)=0

We add all the numbers together, and all the variables

31b-7(-38b+21)-(8(36b+32)-22b)=0

We multiply parentheses

31b+266b-(8(36b+32)-22b)-147=0



We calculate terms in parentheses: -(8(36b+32)-22b), so:

8(36b+32)-22b

We add all the numbers together, and all the variables

-22b+8(36b+32)

We multiply parentheses

-22b+288b+256

We add all the numbers together, and all the variables

266b+256

Back to the equation:

-(266b+256)



We add all the numbers together, and all the variables

297b-(266b+256)-147=0

We get rid of parentheses

297b-266b-256-147=0

We add all the numbers together, and all the variables

31b-403=0

We move all terms containing b to the left, all other terms to the right

31b=403

b=403/31

b=13

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