31=5(u+5)-7u

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Solution for 31=5(u+5)-7u equation: 



31=5(u+5)-7u

We move all terms to the left:

31-(5(u+5)-7u)=0



We calculate terms in parentheses: -(5(u+5)-7u), so:

5(u+5)-7u

We add all the numbers together, and all the variables

-7u+5(u+5)

We multiply parentheses

-7u+5u+25

We add all the numbers together, and all the variables

-2u+25

Back to the equation:

-(-2u+25)



We get rid of parentheses

2u-25+31=0

We add all the numbers together, and all the variables

2u+6=0

We move all terms containing u to the left, all other terms to the right

2u=-6

u=-6/2

u=-3

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