31=4+9(h+5)

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Solution for 31=4+9(h+5) equation: 



31=4+9(h+5)

We move all terms to the left:

31-(4+9(h+5))=0



We calculate terms in parentheses: -(4+9(h+5)), so:

4+9(h+5)

determiningTheFunctionDomain
9(h+5)+4

We multiply parentheses

9h+45+4

We add all the numbers together, and all the variables

9h+49

Back to the equation:

-(9h+49)



We get rid of parentheses

-9h-49+31=0

We add all the numbers together, and all the variables

-9h-18=0

We move all terms containing h to the left, all other terms to the right

-9h=18

h=18/-9

h=-2

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